Answer:
x=\frac{25-\sqrt{130}}{3}
Explanation:
x_{1,\:2}=\frac{-100\pm \sqrt{100^2-4\left(-6\right)\left(-330\right)}}{2\left(-6\right)}
x_{1,\:2}=\frac{-100\pm \:4\sqrt{130}}{2\left(-6\right)}
x_1=\frac{-100+4\sqrt{130}}{2\left(-6\right)},\:x_2=\frac{-100-4\sqrt{130}}{2\left(-6\right)}
x=\frac{25-\sqrt{130}}{3},\:x=\frac{25+\sqrt{130}}{3}