Question

PLEASE HELP ASAP

1) During a transformation, a positive radon nucleus repels a positive helium nucleus
(m = 6.64 × 10–27 kg), giving it an energy of 7.37 × 10–13 J. How fast is the helium
nucleus moving when it is far away from the radon nucleus? Draw an energy bar chart
to assist you.

2) A positive charge of +7.2 μC and a positive charge of +6.64 μC are 10 cm apart, at
rest. After t seconds, the particles are at a distance 15 meters apart with velocities
–8.7 m/s and 9.1 m/s, respectively. Draw an energy bar chart of the situation and
determine the direction of the forces and velocities of each charge.

Answer 1

To find the velocity of the helium nucleus when it is far away from the radon nucleus, we can use the principle of conservation of energy and draw an energy bar chart. By calculating the initial and final kinetic energies of the helium nucleus, we can determine its velocity.

Step-by-step explanation:

The problem involves a positive radon nucleus repelling a positive helium nucleus in a transformation, and we need to find the velocity of the helium nucleus when it is far away from the radon nucleus. To solve this problem, we can use the principle of conservation of energy and draw an energy bar chart.

1. First, we calculate the initial kinetic energy of the helium nucleus, which is equal to the energy given to it by the radon nucleus.
2. Next, we calculate the final kinetic energy of the helium nucleus when it is far away from the radon nucleus. Since there is no external work done on the nucleus and no potential energy involved, the final kinetic energy is equal to the initial kinetic energy.
3. Finally, we use the formula to calculate the velocity of the helium nucleus when it is far away from the radon nucleus.