Question

What is the centripetal force exerted on a 3.21 kg mass that is orbiting at a speed of 4.57 m/s around a circle, radius 0.68 m?

Question 6 options:

1)

9.98 N

2)

30.7 N

3)

21.6 N

4)

316 N

5)

98.6 N

Answer 1

The centripetal force on a 3.21 kg mass rotating at 4.57 m/s around a circle of 0.68 m radius is calculated using the formula Fc = m * v² / r, giving 98.6 N.

Step-by-step explanation:

The centripetal force exerted on a 3.21 kg mass that is orbiting at a speed of 4.57 m/s around a circle with a radius of 0.68 m can be calculated using the formula Fc = m * v² / r, where Fc is the centripetal force, m is the mass, v is the velocity, and r is the radius of the circle.

To find the centripetal force, we plug the values into the equation, resulting in Fc = (3.21 kg) * (4.57 m/s)² / (0.68 m).

Performing the calculation gives us Fc = 3.21 kg * 20.8849 m²/s² / 0.68 m which equals 98.6158824 N, which can be rounded to 98.6 N.

Therefore, the correct option is (5) 98.6 N.