Question

Find the area of the triangle formed by x intercepts and y intercepts of the parabola y=4x^2-8x-5

PLEASE HELP ASAP
SHOW ALL WORK USING VERTEX FORM!!!!!

Answer 1

7.5 unite square

Explanation:

someone already explained so i will just tell you the steps. I deeply apologize for the inconvieence, grammer mistakes, and lack of showing work.

step 1.

find the x- and y intercepts

step 2.

find the vertexes

step 3.

pug the points onto the cordiante plane

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Answer 2

• 7.5 unit²

Explanation:

Refer to attached

Find the y-intercept:

• x = 0 ⇒ y = 4*0 - 8*0 - 5 = - 5

Find the x-intercepts:

• y = 0 ⇒ 4x² - 8x - 5 = 0
• 4x² - 8x + 4 - 9 = 0
• 4(x - 1)² = 9
• (x - 1)² = 9/4
• x - 1 = 3/2 ⇒ x = 2.5
• x - 1 = - 3/2 ⇒ x = - 0.5

We have vertices of the triangle at:

• (- 0.5, 0), (2.5, 0) and (0, -5)

Base of the triangle is:

• 2.5 - (-0.5) = 3

Height of triangle:

• 0 - (-5) = 5

The area is:

• A = 1/2bh
• A = 1/2*3*5 = 7.5