Answer: 15 students in her second class.
Explanation:
Let A, B, and C stand for the number of students in each class. See the attached table.
The column labelled "Students" is formed by assinging B to the second class and finding how the other two classes relate to B. Class A has twice as many students as class B, so A = 2B. Class C has 5 more students than B, so C = B+5.
The total students amount to 65, whcih is the sum of A, B, and C:
A + B + C = 65
Substitute the values of A and C into this equation:
A + B + C = 65
2B + B + (B+5) = 65
4B + 5 = 65
4B = 60
B = 16
Use B=16 and solve for the other two classes (dotted blue line).