Question

What is the equation of the line that passes through each pair of points for (-2,3) (3,-2)

Answer 1

y = -x + 1

Explanation:

slope = (y2-y1)/(x2-x1) = (-2-3)/(3-(-2)) = -5/5 = -1

y-int: y=mx+b --> plug in a point --> 3 = (-1)(-2)+b --> b=1

y = -x + 1

Answer 2

y = -x + 1

example:

(-2, 3)

y = -(-2) + 1

y = 2 + 1

y = 3