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how long in seconds would it take a rock to fall 450 feet and what would be the final velocity of the rock in miles per hour when it hit the ground

User Vzurd
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1 Answer

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Answer:

S = Vy t + 1/2 g t^2 = 1/2 g t^2 vertical speed with zero initial speed

t = (2 S / g)^1/2 with g = 32 ft/sec^2

t = (900 / 32)^1/2 = 5.30 sec time to reach ground

V = a t = 32 ft/s^2 * 5.30 s = 170 ft/sec

170 ft/sec / (88 ft/sec / 60 mph) = 116 mph since 88 ft/sec = 60 mph