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A gas has a volume of 0.215 L and a temperature of -20.0 oC. The gas is heated to 60.0 oC at constant pressure. What will happen to the volume of the gas

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Answer:

V1/T1 = V2/T2

we must convert temperature from °c to kelvin

so T1= -20+273.15=253.15

and T2 = 60 +273.15= 333.15

0.215/253.15= V2/333.15

V2= 0.28L

hence, volume increases a little bit

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