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3 votes
4.

Which of the following is the minimum value of the function y= 1/2x^2 + 2x + 8?

A. 8

B. 0

C. 4

D. 6

User MoienGK
by
8.4k points

2 Answers

5 votes

Answer:

Explanation:

User Nuclearnova
by
7.5k points
0 votes
Start by using -b/2a to find the x value of the vertex (which is where the minimum value would be).
-2/1 = -2 = x value of the vertex
Plug in the x value of the vertex to get the minimum value
1/2(-2)^2 + 2(-2) + 8
2 - 4 + 8
6 = y value of the vertex, which is also the minimum.
Therefore, the minimum value of the function is D. 6
User Katara
by
8.1k points

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