Question

B(n)=−8−2(n−1)b, left parenthesis, n, right parenthesis, equals, minus, 8, minus, 2, left parenthesis, n, minus, 1, right parenthesis

Find the 9^\text{th}9
th
9, start superscript, start text, t, h, end text, end superscript term in the sequence

Answer 1

To find the 9th term of the sequence b(n)=−8−2(n−1), substitute n with 9 to get b(9) = -24, making -24 the 9th term.

Step-by-step explanation:

The question is about finding the 9th term of a recursive sequence defined by b(n)=−8−2(n−1). To find the 9th term in this sequence, we substitute n with 9.

b(9) = -8 - 2(9 - 1)
b(9) = -8 - 2(8)
b(9) = -8 - 16
b(9) = -24

The 9th term in the sequence is -24.