Answer: x = 3.030631 approximately
Step-by-step explanation:
If you want to solve for x, then you could follow these steps:
![18 = 1.57*x^(2.2)\\\\18/1.57 = x^(2.2)\\\\11.464968 \approx x^(2.2)\\\\x^(2.2) \approx 11.464968\\\\x \approx (11.464968)^{(1)/(2.2)}\\\\x \approx 3.030631\\\\](https://img.qammunity.org/2022/formulas/mathematics/high-school/ljgtp8x8cmd9h6cx5ybw6md5oqjhur48j0.png)
In the second to last step, we have the value 11.464968 raised to the exponent of 1/(2.2) which is done to undo the exponent of 2.2 in the previous line. The rule used is
![a^b = c \to a = c^(1/b)](https://img.qammunity.org/2022/formulas/mathematics/high-school/5raafjwf2s8rk0m77t02vu6on5s9ammi7g.png)