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When using re-grouping to solve 21 x 43, what are the four products that would be calculated and then added? 800 + 3 80 + 40 + 60 + 3 800 + 40 + 60 + 3 800 + 40 + 6 + 3
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2 votes
When using re-grouping to solve 21 x 43, what are the four products that would be calculated and then added?

800 + 3
80 + 40 + 60 + 3
800 + 40 + 60 + 3
800 + 40 + 6 + 3

User RomanHotsiy
by
5.4k points

2 Answers

0 votes
The third one because 21 times 43 is 903 and 800 + 40 + 60 + 3 = 903
User Leonid Shumakov
by
5.6k points
3 votes

Answer:

c

Explanation:

21×43

=(20+1)×(40+3)

=800+40+60+3

User Vasil Rashkov
by
6.1k points
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