Question

A line contains the points (-6, -4) and (0,4). What is the equation of this

line in slope-intercept form?
4
OA) y=3*+
x+4
(
4
OB) y=
3
ОВ)
X-4
OC) y=x-4
OD) y=x+4

Answer 1

A)
`y=(4)/(3)x+4`

Explanation:

Write the slope formula:

`m=(y_2-y_1)/(x_2-x_1)`

________________________________________________________

Substitute and calculate

`Substitute:`
`x_1=-6\\ x_2=0\\ y_1=-4\\ y_2=4`
`into\ m=(y_2-y_1)/(x_2-x_1)`

Substitute

`m=(4-(-4))/(-(-6))`

Determine the sign

`m=(4+4)/(6)`

Calculate the sum or difference

`m=(8)/(6)`

Cross out the common factor

`m=(4)/(3)`

________________________________________________________

Substitute and calculate

`Substitute`
`m=(4)/(3)\\ x=-6\\ y=-4`
`into\ y=mx+b`

Substitute

`-4=(4)/(3)*(-6)+b`

Reduce the expression to the lowest term

`-4=-4*2+b`

Calculate the product or quotient

`-4=-8+b`

Rearrange variables to the left side of the equation

`-b=-8+4`

Calculate the sum or difference

`-b=-4`

Divide both sides of the equation by the coefficient of variable

`b=4`

________________________________________________________

Substitute

`Substitute`
`y=(4)/(3)x+4\\ m=(4)/(3)`
`into\ y=mx+b:`

`y=(4)/(3)x+4`

________________________________________________________

Rewrite the equation of the line

`Rewrite\ y=(4)/(3)x+4\ in\ slope-intercept\ form:`

`y=(4x)/(3)+4`

I hope this helps you

:)

Answer 2

As y=4x−2 can be written as y=4x+(−2) . Hence, it's slope is 4 and intercept on y -axis is −2