Answer: Let the points be A(1,1) and B(2,3)
Slope of AB=
2−1
3−1
=2
Product of slope of a line and its perpendicular is −1
⇒ Slope of perpendicular =−
2
1
Mid point of AB is
(
2
1+2
,
2
1+3
)
(
2
3
,2)
So the equation of perpendicular is
y−2=−
2
1
(x−
2
3
)
4y−8=−(2x−3)
2x+4y=11
2x+4y−11=0
Explanation: