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What would be the freezing point of a solution that has a molality of 1.506 m which was prepared by dissolving biphenyl (C12H10) into naphthalene

User JanDro
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The freezing point of a solution prepared by dissolving biphenyl (C12H10) into naphthalene is 67.99oC.

Freezing point can be obtained from;

ΔT = K m i

ΔT = freezing point depression

m = molality of the solution = 1.506 m

i = Van't Hoff factor = 1 for molecular substances

K = Freezing constant of naphthalene = 8.15 oC/m

ΔT = 8.15 oC/m × 1.506 m × 1 = 12.27oC

Freezing point of pure naphthalene = 80.26 °C

ΔT = Freezing point of pure naphthalene - Freezing point of solution

Freezing point of solution = Freezing point of pure naphthalene - ΔT

Freezing point of solution = 80.26 °C - 12.27oC = 67.99oC

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User Yocasta
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