Question

E5. A ball is thrown downward with an initial velocity of 12 m/s.

Using the approximate value of g 10 m/s2, what is the
velocity of the ball 1.0 seconds after it is released?

Answer 1

Hi there!

We know the following kinematic equation:

vf = vi + at

Where:

vf = final velocity

vi = initial velocity

a = acceleration

t = time

In this instance, the ball is experiencing a constant acceleration of that of gravity, thus:

vf = 12 + 10(1) = 22 m/s (if downward is considered positive in this instance)