Hello!
In this diagram, we know that there are 3 forces acting on the block:
W = weight of block ⇒ 2(9.8) = 19.6 N
T1 = HORIZONTAL force
T2
The vertical component of T2 is the only other force keeping the system in equilibrium, so:
∑Fy = 0 = T2y - W
W = T2y
19.6 = T2y
Divide by sine:
19.6/sin(30) = 39.2 N = T2
In the horizontal direction, the body is also at equilibrium involving the HORIZONTAL component of T2 and T1, so:
∑Fx = 0 = T2cos(30) - T1
T1 = T2cos(30)
Use the previously solved-for value for T2:
T1 = (39.2N)(cos(30)) = 33.95 N