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If y²-16y+k is a perfect square, find k​

1 Answer

5 votes

Answer:

k=64

Explanation:

(y-x)(y-x) = y^2-16y+k

Since the k is a "+," and two negatives (hence the negative middle value) multiply to make a positive, and since 16 has to be equal to 2x, we know that x is 8. Therefore, our equation is (y-8)(y-8), which is equal to y^2-16y+64.

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