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1 vote
In a bag of m&ms, there are 12 blue,7 browns, 16 red,6 green, 4 yellow, 8 orange.What is the probability of choosing a brown or green candy from the bag

User Ronen
by
4.5k points

2 Answers

5 votes

Answer:

13/53

Explanation:

Total number of m&m's = 53

Probability of choosing a brown candy = 7/53

Probability of choosing a green candy = 6/53

Probability of choosing a green or brown candy

= 7/53 + 6/53

=13/53

User Corie
by
4.3k points
3 votes

Answer:

40 percent

Explanation:

User Aqib Shahzad
by
4.6k points