Question

Evaluation the following:

A.

`\sqrt{ \frac{32 {y}^(2) }{72 {x}^(2) } }`
B.

`\sqrt[3]{ \frac{125 {m}^(3) }{36 {m}^(2) } }`
C. if

`x1 = 2 \: and \: x2 = 1 \\ and \: y1 = 3 \: and \: y2 = - 1`
then find the value of :

`\sqrt{ (x2)/(y2) - (y2)/(x2) }`
​

Answer 1

A. √32y²/72x²= 32y/72x

Explanation:

√32y²/72x²= 32²/72²

= 32/72.

B. √125m³/36m²

=4192.6/108

=38.8203.

C. √x²/y²-y²/x²

therefore, x²=1, y²=-1

that is, √1/-1 - -1/1= -1(-)-1=0.