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WHAT IS THE AREA OF THE CURVED SURFACE OF A CYLINDER OF BASE RADIUS 4 CM AND HEIGHT 10 CM

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Answer:

The curved surface area of cylinder is 251.42 cm².

Step-by-step Step-by-step explanation:

Here's the required formula to find the curved surface area of cylinder :


\star\underline{\boxed{\sf{CSA_((Cylinder))} = 2\pi rh}}

  • Csa = Curved surface area
  • π = 22/7
  • r = radius
  • h = height

Substituting all the given values in the formula to find the curved surface area of cylinder :


\implies{\tt{CSA_((Cylinder))= 2\pi rh}}


{\implies{\tt{CSA_((Cylinder)) = 2 * (22)/(7) * 4 * 10}}}


{\implies{\tt{CSA_((Cylinder)) = 2 * (22)/(7) * 40}}}


{\implies{\tt{CSA_((Cylinder)) = (2 * 22 * 40)/(7)}}}


{\implies{\tt{CSA_((Cylinder)) = (44 * 40)/(7)}}}


{\implies{\tt{CSA_((Cylinder))= (1760)/(7)}}}


{\implies{\tt{CSA_((Cylinder)) \approx 251.42 }}}


{\star{\underline{\boxed{\tt{\red{CSA_((Cylinder)) \approx 251.42 \: {cm}^(2)}}}}}}

Hence, the curved surface area of cylinder is 251.42 cm².


\rule{300}{2.5}

User Chetan Singhal
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