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Write the equation of the line that passes through the points (2 , -1) and has a slope of - 3​

User Blobdon
by
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2 Answers

3 votes

Answer:

y=-3x+5

Explanation:

y=mx+b

m=slope or gradient (=-3)

y=-3x+b

Add your points

(2, -1)

-1=(-3 x 2)+b

-1= -6+b

-1+6=b

b=5

y=-3x+5

User NicholasByDesign
by
8.3k points
2 votes

Answer:


\boxed {\boxed {\sf y= -3x+5}}

Explanation:

We are asked to find the equation of the line that passes through the point (2, -1) and has a slope of -3.

We are given a point and the slope, so we can use the point-slope formula.


y-y_1=m(x-x_1)

In this formula, m is the slope and (x₁, y₁) is the point the line passes through.

The line has a slope of -3 and passes through (2, -1).

  • m= -3
  • x₁= 2
  • y₁= -1

Substitute the values into the formula.


y--1= -3 (x-2)


y+1= -3 (x-2)

Distribute the -3 on the right side. Multiply each term inside the parentheses by -3.


y+1 = (-3*x) + (-3*-2)


y+1=(-3x) + (6)


y+1=-3x+6

Subtract 1 from both sides of the equation to isolate the variable y.


y+1-1=-3x+6-1


y=-3x +5

The equation of the line is y= -3x+5.

User Alan Rowarth
by
8.3k points

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