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Find the equation of a line that is parallel to y=3+2x that goes through the point (-4,5)

User Fathy
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1 Answer

3 votes

Answer:

y-5=2(x+4) - this equation is in point-slope form. The equation in slope-intercept form is y=2x+13

Explanation:

Since the line is parallel, the slope is the exact same. Since we have the info of the slope and a point on the line, the most obvious choice would be to put in point-slope form, which is y-5=2(x+4). Now, if ht equation is needed in slope -intercept form, you can use algebraic processes to convert. First, I would distribute the 2 into the expression in the parenthesis( multiply everything in the expression by 2), which would make the equation y-5=2x+8. Then, I would subtract 5 from both sides of the equation to isolate the y variable, which would give me y=2x+13. Now, the equation is in slope-intercept form.

User DuckQueen
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