Question

An object weighs 573.0 N on planet Xyleneer. If the object's mass is 92.1 kg, what is the acceleration due to gravity on planet Xyleneer?

Answer 1

a = 6.22 m//s²

Step-by-step explanation:

F = ma

a = F/m

a = 573.0 / 92.1

a = 6.221498...

Answer 2

`\boxed {\boxed {\sf 6.22 \ m/s^2}}`

Step-by-step explanation:

We are asked to find the acceleration due to gravity on another planet.

Weight is the measure of the force of gravity. Therefore, we can use the following version of the force formula:

`F_g=mg`

In this formula,
`F_g` is the weight, m is the mass, and g is the acceleration due to gravity.

The object weights 573.0 Newtons (or 573.0 kg*m/s²) on the planet. The object has a mass of 92.1 kilograms.

• 
  `F_g`= 573.0 kg* m/s²
• m= 92.1 kg

Substitute these values into the formula.

`573.0 \ kg*m/s^2 = 92.1 \ kg * g`

We are solving for g, so we must isolate the variable. It is being multiplied by 92.1 kilograms. The inverse of multiplication is division, so divide both sides of the equation by 92.1 kg.

`\frac {573.0 \ kg*m/s^2}{92.1 \ kg}= (92.1 \ kg*a)/(92.1 \ kg)`

`\frac {573.0 \ kg*m/s^2}{92.1 \ kg}=a`

The units of kilograms cancel.

`6.22149837 \ m/s^2=a`

The original measurements of weight and mass have 4 and 3 significant figures. Our answer must have the least number of sig figs, or 3. For the number we found, that is the hundredth place. The 1 in the thousandths place tells us to leave the 2 in the hundredth place.

`6.22 \ m/s^2=a`

The acceleration due ot gravity on planet Xyleneer is approximately 6.22 meters per second squared.