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33 votes
33 votes
The population of a city increased from 805,743 in 1995 to 1,013,751 in 2005. What is the percent of increase? Round to the nearest tenth of a percent.

User Akhanubis
by
2.8k points

1 Answer

12 votes
12 votes

Answer:

26%

Explanation:

Given:

The population of a city increased from 805,743 in 1995 to 1,013,751 in 2005.

Percent of Change:

Increase divide by Original times 100

Solve:

1,013,751 - 805,743 = 208,008

208,008 ÷ 805,743 × 100

= 25.8156757179

= 26%

~Lenvy~

User Vespino
by
2.5k points
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