Question

What will be the graph of the circle (x-4)^2+(y+3)^2=16

Answer 1

x + y - 5 = 0

Explanation:

(x-4)² + (y+3)² = 16

To remove the square on the left side, we square root both sides

√(x-4)² + √(y+3)² = √16

The square will cancel the square root on the left side, while the square root of 16 is 4

(X-4) + (y+3) = 4

open the brackets

x-4+y+3=4

x + y = 4 + 4 - 3

x + y = 5

x + y - 5 = 0