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What is the equation of the line that passes through the point (-3,-6) and (2,-2)

User Mdicosimo
by
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1 Answer

2 votes

Answer:


y=(4)/(5)x-(18)/(5)

Explanation:

Hi there!

We want to find the equation of the line that passes through the point (-3, -6) and (2, -2)

There are 3 ways to write the equation of the line:

  • In slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept
  • In point-slope form, which is
    y-y_1=m(x-x_1), where m is the slope and
    (x_1,y_1) is a point
  • In standard form, which is ax+by=c, where a, b, and c are integer coefficients, but a and b cannot be zero, and a cannot be negative

The easiest way would either be slope-intercept or point-slope form, but let's write the equation in slope-intercept form, since it's the most common way

So we'll need to find the slope

The formula for the slope calculated from 2 points is
(y_2-y_1)/(x_2-x_1), where
(x_1, y_1) and
(x_2, y_2) are points

We have everything needed to find the slope, let's just label the values of the points to avoid any confusion:


x_1=-3\\y_1=-6\\x_2=2\\y_2=-2

Now substitute these values into the formula. Remember that m is the value of the slope:

m=
(y_2-y_1)/(x_2-x_1)

m=
(-2--6)/(2--3)

Simplify the fraction:

m=
(-2+6)/(2+3)

Add the numbers together:

m=
(4)/(5)

So the slope of the line is 4/5

Let's plug it into the formula y=mx+b, since we now know the value of m

y=
(4)/(5)x+b

Now let's find b

As the equation passes through both (-3, -6) and (2, -2), we can use either point to help solve for b

Either point works, but let's take (2, -2) for instance

Substitute 2 as x and -2 as y

-2=4/5(2)+b

Multiply

-2=8/5+b

subtract 8/5 from both sides

-18/5=b

Now substitute -18/5 as b into the equation:


y=(4)/(5)x-(18)/(5)

Hope this helps!

User Mstaffeld
by
7.3k points

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