Question

The specific heat capacity of liquid water is 4.18 J/g-K. How many joules of heat are needed to raise the temperature of 5.00 g of water from 22.0 °C to 57.0 °C?

Answer 1

731.5j.

Step-by-step explanation:

Basic Formula : Q = mcT.

Q - Heat gained or lost.

m - mass of the given substance.

c - specific heat capacity.

T - Change in temperature ( it often has a delta(triangle) before it.

so now we are directly asked to find the heat.

Q = mcT

m= 5g

c = 4.18

but T = 35k which means 35 kelvin.

why? because you will need to convert the two given initial and final temperatures inorder to cancel the unit kelvin out from the formula above. the target is simply to make the unit J - joule be left alone.

now We convert celsius temperature to kelvin by adding a constant of 273.15 approximately 273.

therefore - Tk = Tc + 273

which will be equivalent to 295k for the initial temperature and 330k for the final.

now granted...keep in mind to use the CHANGE in temperature which is the difference of the 2 kelvin temperatures we just converted

so T = 330k - 295k = 35k

then just substitute everything in the very 1st formula i stated above.

Q = mcT = 5 x 4.18 x 35 = 731.5 J

peace to you.