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What is the y-intercept of the graph of the equation y =(2x−3)^2+7

User Yanike
by
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1 Answer

3 votes

Answer:

(0,16)

Explanation:

Hi there!

The y intercept is the value in which the parabola passes through the y axis

Therefore, the value of x at the y intercept is 0

So to find the value of the y intercept, substitute x as 0 in the equation.

y=(2x-3)^2 + 7

If x=0, then:

y=(2(0)-3)^2 + 7

Multiply

y=(0-3)^2 + 7

Subtract 3 from 0

y=(-3)^2 + 7

Raise -3 to the second power

y= 9 + 7

Add 9 and 7 together

y = 16

So the y intercept is the point (0,16)

Hope this helps!

User Anandh Krishnan
by
8.4k points

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