Question

N a basketball tournament, Team A scored 5 less than twice as many points as Team B. Team C scored 80 more points than Team B. The combined score for all three teams was 983 points. Let the variable b represent Team B’s total points. The equation representing this scenario is (2b – 5) + b + (b + 80) = 983. How many points did Team B score?

1. Combine like terms: 4b + 75 = 983

2. Use the subtraction property of equality: 4b = 908

3. Use the division property of equality: b =

Answer 1

represent team b as b number of team a is five than twice as much point as team b=(2b_5)

team c scored 80 more than b that is (b+80) total number=983

so

Answer 2

Let us assume number of points scored by Team B = b points.

Number of points scored by Team A 5 fewer than twice as many points as Team B, that is "5 less than 2b" = (2b-5) points .

Team C scored 80 more points than Team B, that is " 80 more than b" = (b+80) points.

Total number of points scored by all teams = 983 points.

Therefore, we can setup an equation:

(2b-5) + b + (b+80) = 983.

Therefore, an equation to represent this scenario using the variable b to represent Team B’s total points is (2b-5) + b + (b+80) = 983.

Explanation: