Question

A plane maintains constant acceleration and its velocity increases

from 40m/s to 100m/s over a 10 second interval. What is the plane's
average Distance ?

Answer 1

First calculate a, the acceleration of the plane, given by the equation;

`\alpha = (vf - vi)/(t) = (100 - 40)/(10) = (60)/(10) = 6`

The use the relation given by

Vf²-Vi²=2ad

`d = \frac{100 {}^(2) - 60 {}^(2) }{2 * 6} = (10000 - 3600)/(12) = (6400)/(12) = 533.33 \: meters`