Question

Consider the quadratic function.

f(x)=x^(2)+2x-15
If the line of symmetry of the function is located at x=N, what is the value of N?
HELP ASAP

Answer 1

N = -1

Step-by-step explanation:

x = N

solving steps:

`\sf f(x)=x^2+2x-15`

To find symmetry of a quadratic function.

vertex formula :
`\sf x=(-b)/(2a)`

`a=1,\:b=2`

`\sf x=(-2)/(2\cdot \:1)`

`\sf x = -1`

Then,

N = -1