Consider the quadratic function. f(x)=x^(2)+2x-15 If the line of symmetry of the function is located at x=N, what is the value of N? HELP ASAP

asked Aug 21, 2023 45.0k views

7 votes

Consider the quadratic function.

f(x)=x^(2)+2x-15
If the line of symmetry of the function is located at x=N, what is the value of N?
HELP ASAP

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8 votes

Answer:

N = -1

Step-by-step explanation:

x = N

solving steps:

$\sf f(x)=x^2+2x-15$

To find symmetry of a quadratic function.

vertex formula :
$\sf x=(-b)/(2a)$

$a=1,\:b=2$

$\sf x=(-2)/(2\cdot \:1)$

$\sf x = -1$

Then,

N = -1

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