45.0k views
7 votes
Consider the quadratic function.

f(x)=x^(2)+2x-15
If the line of symmetry of the function is located at x=N, what is the value of N?
HELP ASAP

User MaanooAk
by
3.2k points

1 Answer

8 votes

Answer:

N = -1

Step-by-step explanation:

x = N

solving steps:


\sf f(x)=x^2+2x-15

To find symmetry of a quadratic function.

vertex formula :
\sf x=(-b)/(2a)


a=1,\:b=2


\sf x=(-2)/(2\cdot \:1)


\sf x = -1

Then,

N = -1

User Charles Truluck
by
3.6k points