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If tan^2 = 1-a^2, then the value of sec+tan^3 cosec is

Pls explain fast

User KoemsieLy
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Answer:

for example okk then you will try

Answer: (1) (2 – e2)3/2

Solution:

Given,

tan2θ = 1 – e2

sec θ + tan3θ cosec θ

= sec θ + (sin3θ/cos3θ) (1/sin θ)

= sec θ + tan2θ sec θ

= sec θ(1 + tan2θ)

= √(1 + tan2θ) (1 + tan2θ)

= (1 + tan2θ)3/2

= (1 + 1 – e2)3/2

= (2 – e2)3/2

User BinaryNexus
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