Question

A probe orbiting Venus exerts a gravitational force of 2. 58 × 103 N on Venus. Venus has a mass of 4. 87 × 1024 kg. The mass of the probe is 655 kilograms. The gravitational constant is 6. 67 × 10-11 N*m2/kg2. To three significant digits, the probe is × 106 m from the center of Venus.

Answer 1

9.08

Step-by-step explanation:

To solve for the distance between the probe and the center of Venus, use the formula:

`\mathrm{F = (G\: m1 \:m2)/(r^2)}`

Plugin the values:

G =

`6.67*10^(-11) \mathrm{(m3)/(kg\: s2)}`

`\mathrm{F} =2.58 * 10^3\mathrm{N}`

`\mathrm{m1 = 4.87 * 10^(24)\:kg}`

`\mathrm{m2 = 655\: kg}`

Hence:

`\mathrm{F = (G\: m1 \:m2)/(r^2)}`

`2.58 * 10^(23) = 6.67 * 10^(-11) (4.87 * 10^(24))`

`((655))/(r^2)`

`\mathrm{r = 9.08 * 10^6 \:km}`