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1 vote
Use point-slope form to write the equation of a line that passes through the point

(-3, -16) with slope -
1/2

User Justin Lam
by
8.2k points

2 Answers

3 votes

Answer:


y= -\frac12 x +\frac{29}2

Explanation:

Let's start with the point- slope form:


y-y_0=m(x-x_0)

and replace the values we have


y-(-16) = -\frac12 (x-(-3))

We're almost there, we just need to write it in a better looking form.


y+16= -\frac12 (x+3)\\y=-\frac12 x - \frac32 + \frac{32}2\\y= -\frac12 x +\frac{29}2

User Aochagavia
by
8.1k points
7 votes

Answer:

Explanation:

Point slope form: y - y1 = m(x -x1)


y - [-16] = (1)/(2)(x - [-3] )\\\\y + 16 = (1)/(2)(x + 3)\\\\\\y + 16 = (1)/(2)x + (3)/(2)\\\\y =(1)/(2)x+(3)/(2)-16\\\\y=(1)/(2)x +(3)/(2)-(32)/(2)\\\\\\y=(1)/(2)x - (29)/(2)

User Joel Cunningham
by
8.2k points

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