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A salute of hydrochloric acid has a molarity of 4.0m HCL. if a reaction requires 0.73 g of HCl what volume of the solution should be used?

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Answer:

Step-by-step explanation:

Molar weight of HCl is 36.46g/mole

The reaction requires 0.73 g of HCl so it requires

0.73/36.46 = 0.02 mole of HCl

Molarity of HCl is 4.0M = 4mole/liter

0.02/4 = 0.005L = 5mL

5 mL of HCl solution should be used.

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