Answer:
Step-by-step explanation:
Molar weight of HCl is 36.46g/mole
The reaction requires 0.73 g of HCl so it requires
0.73/36.46 = 0.02 mole of HCl
Molarity of HCl is 4.0M = 4mole/liter
0.02/4 = 0.005L = 5mL
5 mL of HCl solution should be used.
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