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How do you find the parallel component of force (Fsub||) on an inclined plane? Is it equal to the y-component? I also need to find applied force. Mass = 100 kg Weight = 980 N Normal Force = 965 N Theta
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How do you find the parallel component of force (Fsub||) on an inclined plane? Is it equal to the y-component? I also need to find applied force.

Mass = 100 kg
Weight = 980 N
Normal Force = 965 N
Theta = 10°
Friction = 289.5 N

Please Help :) ​

User SHS
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4.9k points

1 Answer

3 votes

Answer:

just add them all up i think i dont know

Step-by-step explanation:

User Nateisha
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