Answer:
or
![(-(19)/(3), 4)](https://img.qammunity.org/2022/formulas/mathematics/high-school/8z3r197kto1tijy3dq8hklrqcn6u6mnp7t.png)
Explanation:
Given the systems of linear equations, 3x + 6y = 5 and -3x - 3y = 7:
Equation 1: 3x + 6y = 5
Equation 2: -3x - 3y = 7
The best method to use for the given system is the process of elimination, since the coefficients of x in both equations have opposite signs.
Step 1: Add both equations:
3x + 6y = 5
-3x - 3y = 7
3y = 12
Step 2: Divide both sides by 3:
![(3y)/(3) = (12)/(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ffk4mnhvm6a5mamosaqf6bmsyorwv6he0o.png)
y = 4
Step 3: Substitute the value of y into Equation 1:
3x + 6y = 5
3x + 6(4) = 5
3x + 24 = 5
Step 4: Subtract 24 from both sides:
3x + 24 - 24 = 5 - 24
3x = -19
Step 5: Divide both sides by 3:
![(3x)/(3) = (-19)/(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/7k3yg61drdsf72nyb0u1lf9weyluh42d8c.png)
![x = -(19)/(3)](https://img.qammunity.org/2022/formulas/mathematics/high-school/o299snicer1vsqibwmzssr05e163rn5pye.png)
Verify the validity of x and y as solutions:
Verify whether the values for x and y satisfy both equations:
![x = -(19)/(3), y = 4](https://img.qammunity.org/2022/formulas/mathematics/high-school/x9sh43myn049n1sqi545ejz7si3ayw7y3s.png)
Equation 1: 3x + 6y = 5
![3(-(19)/(3)) + 6(4) = 5](https://img.qammunity.org/2022/formulas/mathematics/high-school/eo35da2gzz1bjribh0iy26ca2vqo3a9p4i.png)
-19 + 24 = 5
5 = 5 (True statement).
Equation 2: -3x - 3y = 7
![-3(-(19)/(3)) - 3(4) = 7](https://img.qammunity.org/2022/formulas/mathematics/high-school/1o7izpabbyawkty0gzj6odrf04txh0wjof.png)
19 - 12 = 7
7 = 7 (True statement).
Therefore, the solutions to the given systems of linear equations are:
, or
.