209k views
4 votes
Helpppppppppppppppppppp

Helpppppppppppppppppppp-example-1
User Krejko
by
8.3k points

1 Answer

2 votes

Answer:

2nd option

Explanation:

given a quadratic in standard form

y = ax² + bx + c

• If a > 0 then minimum vertex

• If a < 0 then maximum vertex

Here a = - 1 < 0 then maximum

The maximum value is the value of the y- coordinate of the vertex

The x- coordinate of the vertex is

x = -
(b)/(2a)

Here a = - 1 and b = 3 , then

x = -
(3)/(-2) =
(3)/(2)

Substitute this value into the equation for corresponding y- value

y = - (
(3)/(2) )² + 3(
(3)/(2) ) - 1 = -
(9)/(4) +
(9)/(2) - 1 = -
(9)/(4) +
(18)/(4) -
(4)/(4) =
(5)/(4)

Then maximum value of
(5)/(4)

User Reynevan
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories