Question

Tiffany has 22 coins that are dimes and quarters. If the value of the coins is $3.70, how many of each coin does she have? Solve algebraically.

Answer 1

10 Quarters

12 Dimes

Step-by-step

Let x = number of quarters (0.25)

22-x=number of dimes (0.10)

.25x +.10(22-x) = 3.70

.25x+2.2(-.10x) =3.70

-.25x -.25

.15x -2.2=3.70

-2.2 -2.2

`(.15x)/(.15) \\`=
`(1.50)/(.15\\)` x=10

So basically...

10 Quarters

22-10=12 So, 12 Dimes