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calculate the Mass of lead that will be deposited from an aqueous solution of lead(2)salt by the same quantity of electricity that deposit 2.7g of copper from an aqueous solution of copper (2)salt​

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Answer:

8.82 gm of Pb

Step-by-step explanation:

Question

calculate the Mass of lead that will be deposited from an aqueous solution of lead(2)salt by the same quantity of electricity that deposit 2.7 g of copper from an aqueous solution of copper (2)salt​Since the oxidation# of the Pb and the Cu is the same, we know that the same amount of electricity that will deposit 1 mole of Cu will deposit 1 mole of Pb

2.7 gm of Cu were deposited

the atomic mass of Cu = 63.5

the number of moles of Cu deposited was 2.7/63.5 = 0.0425 moles

so 0.0425 moles of Pb will be deposited.

The atomic mas of Pb is 207.2

0.0425 mole of Pb weigh 0.0425 X 207.2 =

8.82 gm of Pb

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