Answer:
![t= \frac12C +3](https://img.qammunity.org/2022/formulas/mathematics/high-school/4eqjugaw8hmvbl75ccbw69098ensq5x1eh.png)
Explanation:
Let's first write the data you have in an equation form:
. When t = 0, at dawn, you get -6°C so we're good. But you've ben asked the inverse relationship, so let's solve for t instead.
![-6+2t = C\\2t = C+6\\t= \frac12(C+6)\\t= \frac12C +3](https://img.qammunity.org/2022/formulas/mathematics/high-school/voeijegdvx8uqrjpozy51fbn7o6z7v9npq.png)
Last two are both viable solution, only difference is in form. I do prefer the last option since it makes it easiest at a glance to answer to the question "at what time there's a temperature of 0°C?"