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A skydiver jumps from an airplane that is moving at 50 meters per second at a height of 1,000 meters what describes the skydivers energy immediately after leaving the air plane

User Dozer
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Answer:

11060M Joules, where M is the mass of the diver in kg

Step-by-step explanation:

Mass of the skydiver missing, we're assuming it's M.

It's total energy is the sum of the contribution of his kinetic energy (K)- since he's moving at 50 m/s, and it's potential energy (U), since he's subject to earth gravity.

Energy is the sum of the two, so
E = K+U= \frac 12 M v^2 + Mgh = M (\frac 12 \cdot 50^2 + 9.81\cdot 1000) = M ( 1250 + 9810) = 11060\cdot M

User Beomi
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