Answer: 909.03
Explanation:
We know that the equation is an exponential function, it can be written as y=ab^x
![100 &=a b^(6.5) \dots \mathrm{Equation \ 1} \\11 &= a b^(1) \\](https://img.qammunity.org/2023/formulas/mathematics/middle-school/912qbpb7yl4yz1qa8f2jakq4anzbf2tg1r.png)
![\Rightarrow ab^1=11](https://img.qammunity.org/2023/formulas/mathematics/middle-school/pgndgauc6sp1weqise09vd00fpi2n3horm.png)
![\Rightarrow (ab^1)/(b)=(11)/(b);\quad \:b\\e \:0](https://img.qammunity.org/2023/formulas/mathematics/middle-school/rvtbcq377ccrl51f0llaeujn2hjmalowkn.png)
![\Rightarrow a=(11)/(b)](https://img.qammunity.org/2023/formulas/mathematics/middle-school/t9uulr2e6jxzkloagkg45vxpdonj55b2nv.png)
a = 11/b, substitute it in equation 1
![100 &=a b^(6.5)](https://img.qammunity.org/2023/formulas/mathematics/middle-school/xg3uxwm9kzaz0vsoccfnygf5frm5rdaye2.png)
![\Rightarrow 100=\left((11)/(b)\right)b^(6.5)](https://img.qammunity.org/2023/formulas/mathematics/middle-school/7705dnx82q4xoy4q0ury487quvxxfx2tc8.png)
![\Rightarrow 100b=11b^(11)/(2)](https://img.qammunity.org/2023/formulas/mathematics/middle-school/gq8x4zo5rxylv2yvxw7g13ecbwk5unbwqx.png)
![\Rightarrow 11\sqrt{b^(11) } =100b](https://img.qammunity.org/2023/formulas/mathematics/middle-school/aktr4e5cak2pbrwensqnxosizq16fs0a1b.png)
![\Rightarrow \sqrt{b^(11) } =(100)/(11)}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/gb7zik3p2zo412resj32ktnpskj23uybzh.png)
![\Rightarrow \sqrt{b^(11) } =(100)/(11)}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/gb7zik3p2zo412resj32ktnpskj23uybzh.png)
![\Rightarrow {b^(11) } =(10000)/(121)}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/kr0t5kfei0eyue1v3zts2zsy45m03grjsc.png)
![\Rightarrow {b} =\frac{\sqrt[11]{10000 \cdot 11^9} }{11}](https://img.qammunity.org/2023/formulas/mathematics/middle-school/aktt3f1arzxj859u52s38su8y4s3vq6vy2.png)
![\Rightarrow {b} = 1.49379](https://img.qammunity.org/2023/formulas/mathematics/middle-school/lf94xaiei8tvnhhvob70x9tzvzfbwih6n6.png)
a = 11/b
a = 11/(1.49379)
a = 7.36382
Equation: y = (7.36382)(1.49379)^x
Now plug in 12 for x:
![\Rightarrow { \left(7.36382\right)\left(1.49379\right)^(12)](https://img.qammunity.org/2023/formulas/mathematics/middle-school/vt35047ilohspeqj6ftl7oi6e6rduq0egp.png)
![\Rightarrow 7.36382\cdot \:1.49379^(12)](https://img.qammunity.org/2023/formulas/mathematics/middle-school/33t8aqa8dnfl392vwzaakot8oksdw0uelv.png)
![\Rightarrow 7.36382\cdot \:123.44530\dots](https://img.qammunity.org/2023/formulas/mathematics/middle-school/dbpbp70t17yndrgon9jwof63ti6ll42r07.png)
![\Rightarrow 909.03](https://img.qammunity.org/2023/formulas/mathematics/middle-school/zykcj4luso3vmb29id2yzx9fqwnlrd81ek.png)
Therefore, f(12) = 909.03 for the exponential function