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You pick a card at random. Without putting the first card back, you

pick a second card at random.
What is the probability of picking an odd number and then picking
an even number?
Write your answer as a percentage.

You pick a card at random. Without putting the first card back, you pick a second-example-1
User Slawekwin
by
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1 Answer

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First, we need the probability of picking an odd number.

There are 5 cards in total, and 3 odd cards (3, 5, and 7).

That means that the probability that we'll draw an odd card would be
(3)/(5).

Then, we have 4 cards left, and 2 even cards (4 and 6), meaning that the probability that we draw an even card will be
(2)/(4) or
(1)/(2).

To find the probability that these would happen in consecutive draws, we just multiply the probabilities together.


(3)/(5)*(1)/(2)=(3)/(10) or 0.3.

To convert this into a percentage, we multiply the decimal by 100.


0.3*100=30.

So the probability of picking an odd number and then picking an even number is 30%.

Hope this helps!

User DriverBoy
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