Question

How many moles of NO₂ would be required to produce 5.73 moles of HNO₃ in the presence of excess water in the following chemical reaction?

3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)

Answer 1

8.595 mol NO2

Step-by-step explanation:

5.73 mol HNO3 *
`((3 mol NO2)/(2 mol HNO3))` = 8.595 mol NO2