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Answer:
dy/dx = y/(2x)
Explanation:
The product formula can be used, along with the power rule.
d(uv) = du·v +u·dv
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d(y^2/x) = d(18)
2y·dy/x -y^2/x^2·dx = 0
2x·dy -y·dx = 0 . . . . . . . . multiply by x^2/y
dy/dx = y/(2x) . . . . . . . . add y·dx, divide by 2x·dx