Question

A device has a resistance of 11 Ω and a current of 12 A. What is it power and potential difference?

Answer 1

The potential difference is 132 volt

And the Power is 1584 watt

Step-by-step explanation:

Given :

Reresistance = 11 Ω

current = 12 A

The Potential difference = IR

V= IR

=> V = 11×12

=> V = 132v

Now ,

Power = VI

=> P = 132×12

=> P = 1584 w

Answer 2

Question :-

• A Device has a Resistance of 11 Ohm and a Current of 12 Ampere . What is it Power and Potential Difference .

Answer :-

• Power of the Device is 1584 Watt .
• Potential Difference is 132 Volt .

Explanation :-

As per the provided information in the given question, we have been given that the Resistance of the Device is 11 Ohm . Current is given as 12 Ampere . And, we have been asked to calculate the Power and Potential Difference .

➻ Now here, First we will find the Potential Difference of the Device :-

• V = I R

Where ,

• V denotes to the P.D
• I denotes to the Current
• R denotes to the Resistance

Therefore, by Substituting the given values in the above Formula :-

⇒ P.D = Current × Resistance

⇒ P.D = 11 × 12

⇒ P.D = 132 Volt

Hence ,

• Potential Difference is 132 Volt .

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➻ Now here, we will find the Power :-

• P = V I

Where ,

• P denotes to the Power
• V denotes to the P.D
• I denotes to the Current

Therefore, by Substituting the given values in the above Formula :-

⇒ Power = P.D × Current

⇒ Power = 132 × 12

⇒ Power = 1584 Watt

Hence ,

• Power of the Device is 1584 Watt .

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Note :-

• In the above Answer , kindly refer that P.D denotes to the Potential Difference .