Question

- sinx
dy/dx = ?
cosx or -cosx?

Answer 1

`y = - \sin(x) \\ (dy)/(dx) = - (d)/(dx) ( \sin(x) ) \\ \boxed{ (dy)/(dx) = - \cos(x) }`

• dy/dx = -cos(x) is the right answer.

Answer 2

Explanation:

y=-sinx

dy/dx = d(-sinx)/dt= -cosx

hope it helps